Asked by Vijay
                Q.y=2x 
sir this question answer 2x log 2
            
        sir this question answer 2x log 2
Answers
                    Answered by
            Reiny
            
    According to your suggested answer, I think your function was
y = 2^x
then taking the ln of both sides:
lny = ln(2^x) = x ln2
now differentiate,
y' / y = ln2
y' = y(ln 2) = ln2 (2^x)
you cannot use log2 , it must be ln2
    
y = 2^x
then taking the ln of both sides:
lny = ln(2^x) = x ln2
now differentiate,
y' / y = ln2
y' = y(ln 2) = ln2 (2^x)
you cannot use log2 , it must be ln2
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.