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Solve the system by substitution. -x-y-z=-8 -4x+4y+5z=7 2x+2z=4 I am very confused about this. Can someone please explain how t...Asked by Olivia N J
Solve the system by substitution.
-x-y-z=-8
-4x+4y+5z=7
2x+2z=4
I am very confused about this. Can someone please explain how to do this?
-x-y-z=-8
-4x+4y+5z=7
2x+2z=4
I am very confused about this. Can someone please explain how to do this?
Answers
Answered by
Reiny
The actual steps will vary from person to person, and there is no single way to solve this.
You sort of have to decide on the simplest equation as a starting point.
In this case it is the last equation, it only has two variables.
2x + 2z = 4 , or
x + z = 2 ---> x = 2-z
I will now sub that into the 1st and the 2nd
-x-y-z=-8 ----> x + y + z = 8
2-z + y + z = 8
y = 6 ----> well that was lucky
in the 2nd:
-4x + 4y + 5z = 7
-4(2-z) + 24 + 5z = 7
-8 + 4z + 24 + 5z = 7
9z = -9
z = -1
then x = 2-z = 2+1 = 3
x = 3
y = 6
z = -1
You sort of have to decide on the simplest equation as a starting point.
In this case it is the last equation, it only has two variables.
2x + 2z = 4 , or
x + z = 2 ---> x = 2-z
I will now sub that into the 1st and the 2nd
-x-y-z=-8 ----> x + y + z = 8
2-z + y + z = 8
y = 6 ----> well that was lucky
in the 2nd:
-4x + 4y + 5z = 7
-4(2-z) + 24 + 5z = 7
-8 + 4z + 24 + 5z = 7
9z = -9
z = -1
then x = 2-z = 2+1 = 3
x = 3
y = 6
z = -1
Answered by
Olivia N J
THANK YOU!!!!!!!!!!
Answered by
Reiny
you are welcome
Answered by
DDM
8 x 4 = 32 not 24 XD
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