Asked by bobby mg
If you jumped off a 25 meter cliff on the moon (gravity being 1.66) what would be a comparable hight of that cliff on earth? the answer and show me how to get it.
Answers
Answered by
Henry
0.5g*t^2 = 25.
0.83*t^2 = 25, t = 5.49 s. to reach gnd.
h = 0.5g*t^2 =4.9*5.49^2 = 148 m.
0.83*t^2 = 25, t = 5.49 s. to reach gnd.
h = 0.5g*t^2 =4.9*5.49^2 = 148 m.
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