Asked by IDontKnow
What is the value of t in the equation below?
(7^-64)x(7^-150)/(7^-7)x(7^2)=7^t
Help please i get lost when its a huge problem like this but if it's short i can solve it.
(7^-64)x(7^-150)/(7^-7)x(7^2)=7^t
Help please i get lost when its a huge problem like this but if it's short i can solve it.
Answers
Answered by
Steve
just add exponents when multiplying and subtract when dividing. So,
(7^-64)x(7^-150)/(7^-7)x(7^2)
= 7^(-64-150+7-2)
= 7^-209
so, t = -209
or, knowing that negative exponents mean that you swap places in the fraction, you have
7^7 / (6^64 * 7^150 * 7^2) = 1/7^209
(7^-64)x(7^-150)/(7^-7)x(7^2)
= 7^(-64-150+7-2)
= 7^-209
so, t = -209
or, knowing that negative exponents mean that you swap places in the fraction, you have
7^7 / (6^64 * 7^150 * 7^2) = 1/7^209
Answered by
IDontKnow
its wrong
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