Question

latent heat of fusion of ice is 3.36exp5 j/kg and its specific heat is 1200j/mole.k.. 2kg of ice is at -10degC how much ice will be melt when a heat of 1.42exp5 joule is provided completely? a) 0.5kg b) 1.5kg c) 2kg d) 1kg

Answer 1

heat to warm ice=2*1200/mole*10= 2/18*1200*10= 1.3kJ
heat left over to
melt ice=142kJ-1.3 kJ=140kJ

melting ice:
140kJ=mass*336kJ
massmelted=140/336= about .4kg
closest answer is the lowest one.