Question
The equations
x+ ky + 2z =0
x + (2k-1)y + 3z =0
x + ky + (k+3)z = 2k-1
Find the values of k such that
a) the system has a unique solution
b) the system has no solutions
c) the system has infinitely many solutions
Thanks
x+ ky + 2z =0
x + (2k-1)y + 3z =0
x + ky + (k+3)z = 2k-1
Find the values of k such that
a) the system has a unique solution
b) the system has no solutions
c) the system has infinitely many solutions
Thanks
Answers
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