tension=mg+ma= weight(1+a/g)
weight= 51/(1+1.04/9.8) N
A fisherman is fishing from a bridge and is using a "51.0-N test line." In other words, the line will sustain a maximum force of 51.0 N without breaking. What is the weight of the heaviest fish that can be pulled up vertically, when the line is reeled in with an acceleration whose magnitude is 1.04 m/s2?
2 answers
F = ma
51.0N = m (1.04)
m= 49.0
Weight=mg (g=9.81)
49.0 x 9.81 = 481 N
51.0N = m (1.04)
m= 49.0
Weight=mg (g=9.81)
49.0 x 9.81 = 481 N