Question

A calcium iodide solution is made by mixing 0.520g of calcium iodide with 12.0ml of water.
1) Determine the moles of calcium iodide used to make the solution
2) Determine the mass of solvent used to make the solution. Assume that the density of water is 1.000g/ml.
3) Determine the molality of calcium iodide of the solution.
4) Determine the molality of all solutes of the solution.

Answer 1

1. mols CaI2 = grams/molar mass = ?
2. mass - volume x density = 12.0 mL x 1.000 g/mL = ?
3.m = mols/kg solvent
4. I'm confused about the term "molality of all solutes). I assume you want the m of Ca ion and m of I ion.
m Ca^+ is the same as m CaI2.
m I^- is 2x m CaI2.

Answer 2

Please check if am i got it right
1. mols Cal2 = 0.520g/293.886 = 0.001769g/mol

2. Mass-volume x density
= 12.0ml x 1.00g/ml = 12g/ml
3. M= mols/kg solvant
how do I get kg solvent.
is this right 0.001769/12 to get the ans = 1.47417E-4
4, it says determine the molality of all solutes means all actions and anions. How do I calculate this.