Asked by Kiley
I've been stuck on this physics homework since I got home. I think the main issue I don't get is finding the components, and adding them to find the resultant force or velocity. Here's one problem.
Three forces act on a point concurrently. Force a is 80N at 220 degrees, force b is 70N at 90 degrees, and force c is 70N at 0 degrees. Find the resultant force and equilibrant force.
Please help in anyway, I really do not understand any of this.
Three forces act on a point concurrently. Force a is 80N at 220 degrees, force b is 70N at 90 degrees, and force c is 70N at 0 degrees. Find the resultant force and equilibrant force.
Please help in anyway, I really do not understand any of this.
Answers
Answered by
Damon
x components:
80 cos 220 = -61.3
70 cos 90 = 0
70 cos 0 = 70
total x = 8.72
y components
80 sin 220 = -51.4
70 sin 90 = 70
70 sin 0 = 0
total y = 18.6
so magnitude resultant = sqrt (18.6^2 +8.72^2) = 20.2 Newtons
direction
cos angle = 8.72/20.2
angle = 64.4 degrees
The equilibrant is equal in magnitude and at 64.4+180 = 244.4 degrees
80 cos 220 = -61.3
70 cos 90 = 0
70 cos 0 = 70
total x = 8.72
y components
80 sin 220 = -51.4
70 sin 90 = 70
70 sin 0 = 0
total y = 18.6
so magnitude resultant = sqrt (18.6^2 +8.72^2) = 20.2 Newtons
direction
cos angle = 8.72/20.2
angle = 64.4 degrees
The equilibrant is equal in magnitude and at 64.4+180 = 244.4 degrees
Answered by
hafsa
Equilibrant =0
Answered by
shemsa
quation of physics
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