Asked by hailey
If the coefficient of kinetic friction is .25, how much horizontal force is needed to pull each of the following masses along a rough desk at a constant speed?
a. 25 kg
b. 15 kg
c. 250 g
explain please!!
a. 25 kg
b. 15 kg
c. 250 g
explain please!!
Answers
Answered by
bobpursley
force friction=mu*m*g
at constant velocity, the pushing force is exactly equal to the force of friction, so
pushingforce=mu*mass*accelerationgravity
at constant velocity, the pushing force is exactly equal to the force of friction, so
pushingforce=mu*mass*accelerationgravity
Answered by
hailey
thanks!!!
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