Asked by Angie

y = x^3 - 8x^2 + 6x -2 has a slope of 6 at two points, what are the coordinates?

I used Reiny's way to help solve this answer.
Please check if I've done it correct: y'= 3x^2-16x+6

3x^2-16x+6=6
3x^2-16x=0
x(3x-16)=0
Solve for x's
x=0
3x-16=0 ~> x=16/3

Plug x values to original function

(0)^3 - (8)(0)^2 + 6(0) - 2 = y ~> -2
(16/3)^3 - (8)(16/3)^2 + 6(16/3) - 2 = y ~> -1238/27

Coordinates will be, (0,-2) & (16/3, -1238/27)
Answered by Reiny
correct, see my last response to your previous post of this
Answered by HELP
Im sorry i would help but im not even there in math yet im in 6 grade what grade are you in
Answered by Angie
@Reiny,

Thanks again!
There are no AI answers yet. The ability to request AI answers is coming soon!