Asked by b
Aljhumar is trying to arrange his room. He pushes an 80kg cabinet across the wooden room which resists the motion with a 300N force of friction. What is the coefficient of sliding friction between the cabinet and the floor?
Answers
Answered by
Henry
M*g = 80 * 9.8 = 784 N. = Wt. of cabinet = Normal force(Fn).
Fk = u*Fn. 300 = u*784, u = ?.
Fk = u*Fn. 300 = u*784, u = ?.
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