Asked by Nabsha

Among the following electrons, which has highest energy? a. n = 3, l = 2, m = 0, s = + 1/2 b. n = 4, l = 0. m= 0 , s = - 1/2
Ans is A... but how A? Why nOt B?

Answers

Answered by DrBob222
Look at the order of filling. That is
1s, 2s, 2p, 3s, 3p, 4s, 3d etc.
So if n = 3 and l = 2, the electrons must be a 3d electron. For n = 4 and l = 0, that's a 4s electron. The 4s is lower energy than the 3d. I think B.
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