Asked by bits

a 1240 kg automobile stops in a distance of 41m. if initial velocity was 22.5m/s, what force did the road exert on the car to stop it? Answer pls... Thank You
Answered by Steve
how long does it take to stop, with acceleration a?

22.5t + 1/2 at^2 = 41
Now, with that t,
22.5 + at = 0
That gives you the value of a.

F = ma
Answered by b
How to get acceleration? and time?
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