Asked by Ck
                At the same distance the noise of a sandblaster is  13 dB louder than a power drill. This means the the displacement amplitude of the sound waves from the sandblaster is how many times greater than that of the power drill if both sounds have the same frequency?
            
            
        Answers
                    Answered by
            Henry
            
    20*Log(Ns/Np) = 13.
Log(Ns/Np) = 13/20 = 0.65,
Ns/Np = 10^0.65 = 4.47.
Ns = 4.47Np.
    
Log(Ns/Np) = 13/20 = 0.65,
Ns/Np = 10^0.65 = 4.47.
Ns = 4.47Np.
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