At the top:
mv^2/r=Tension+mg
tension= -mg+mv^2/r
= .285(-9.8+5.25^2/.81)
A ball of mass m 0.285 kg swings in a vertical circular path on a string L = 0.810 m long as in the figure below.
a) If its speed is 5.25 m/s at the top of the circle, what is the tension in the string there? 6.89N (is the answer)
b)If the string breaks when its tension exceeds 20.5 N, what is the maximum speed the ball can have at the bottom before that happens?
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