Question
A 145-kg object and a 445-kg object are separated by 3.90 m.
(a) Find the magnitude of the net gravitational force exerted by these objects on a 34.0-kg object placed midway between them. (N)
(b) At what position (other than an infinitely remote one) can the 34.0-kg object be placed so as to experience a net force of zero from the other two objects?
(m from the 445 kg mass toward the 145 kg mass)
(a) Find the magnitude of the net gravitational force exerted by these objects on a 34.0-kg object placed midway between them. (N)
(b) At what position (other than an infinitely remote one) can the 34.0-kg object be placed so as to experience a net force of zero from the other two objects?
(m from the 445 kg mass toward the 145 kg mass)
Answers
bobpursley
a) net force=G34(445 -145 )/d^2 where d is half the separation distance.
b. let x be the distance from the larger object.
Then the force is zero at that point. 0=G*34(445/x^2-145/(3.9-x)^2
or 445/x^2=145/(3.9-x)^2
(3.9-x)^2=.326 x^2
take sqrt of both sides
(3.9-x)=.571 x
1.571x=3.9
x=2.48m from the larger object
check all that math.
b. let x be the distance from the larger object.
Then the force is zero at that point. 0=G*34(445/x^2-145/(3.9-x)^2
or 445/x^2=145/(3.9-x)^2
(3.9-x)^2=.326 x^2
take sqrt of both sides
(3.9-x)=.571 x
1.571x=3.9
x=2.48m from the larger object
check all that math.
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