Question

Molten Al2O3 is reduced by electrolysis at low potentials and high currents. If 1.5 x 10^4 amperes of current is passed through molten Al2O3 for 8.0 hours, what mass of Al is produced? Assume 100% current efficiency?

Mdep = ([1.5 x 10^ x 28800s ]/ 96500) x (26.98/6e)

= 20130g

gives me the wrong answer tho?

Answer 1

That's 2 Al for 6e or 1 Al for 3e so that factor should be 2*26.98/6e or 26.98/3e. That doubles the answer. Some books use 96,485 instead of 96,500. Thanks for showing your work. That always makes it easier to find the error.