(2x-1)(x+4) = 0
etc
Solve by factoring: 2x^2+7x-4=0
9 answers
Can you explain how to do this one?
Its the same, just a little different setup.
4x^2+10x=x^2-x+4
Its the same, just a little different setup.
4x^2+10x=x^2-x+4
combine like terms
3x^2 + 11x - 4 = 0
(3x-1)(x+4) = 0
etc
3x^2 + 11x - 4 = 0
(3x-1)(x+4) = 0
etc
can you show me how to solve the factored equation?
based on the fact that if a multiplication has an answer of zero then one or more of its factors must have been zero, so if
(3x-1)(x+4) = 0
then 3x-1 = 0 or x+4 = 9
3x = 1 or x = -4
x = 1/3 or x = -4
(set each of the factors equal to zero and solve, separate your statements with OR )
(3x-1)(x+4) = 0
then 3x-1 = 0 or x+4 = 9
3x = 1 or x = -4
x = 1/3 or x = -4
(set each of the factors equal to zero and solve, separate your statements with OR )
Where did the 9 come from in x+4=9?
If you understood the concept you should have figured out that I meant 0 instead of 9
(the 0 is beside the 9 on the keyboard !)
(the 0 is beside the 9 on the keyboard !)
OHHHH. Wow. Haha, sorry, you definitely threw me off with that one. I get it now. Thanks.
solve
42x^2-14x-56=0
42x^2-14x-56=0
1 answer