Asked by Dayshae
Two equal forces, 20 N each, gives you a resultant value of 20 N. What is the angle between the two forces?
Answers
Answered by
bobpursley
draw the diagram.
Law of cosines:
c^2=a^2+b^2-2abcosTheta where theta is the angle between a and b.
400=400+400-800cosTheta
cosTheta=1/2
Theta= arccos(.5)=60 degrees if I remember correctly.
Law of cosines:
c^2=a^2+b^2-2abcosTheta where theta is the angle between a and b.
400=400+400-800cosTheta
cosTheta=1/2
Theta= arccos(.5)=60 degrees if I remember correctly.
Answered by
Steve
I think you will find that theta = 120 degrees. the angle used is cos(180-theta)
There is no way that two 20N vectors pointing in basically the same direction can have a resultant of 20N.
You want the short diagonal of the parallelogram.
There is no way that two 20N vectors pointing in basically the same direction can have a resultant of 20N.
You want the short diagonal of the parallelogram.
Answered by
Vianca
a 50ml volume of gas is measured at 20 degree celsius,if the pressure remains constant what will be the volume of the gas at 0 degree celsius?
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