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Original Question
A bag contains 3 gold marbles, 10 silver marbles, and 21 black marbles. Someone offers to play this game: You randomly select o...Asked by tatiana
A bag contains 2 gold marbles, 7 silver marbles, and 23 black marbles. Someone offers to play this game: You randomly select one marble from the bag. If it is gold, you win $4. If it is silver, you win $2. If it is black, you lose $1.
What is your expected value if you play this game?
What is your expected value if you play this game?
Answers
Answered by
Reiny
expected(gold) = $4(2/32) = 0.25
expected(silver) = $2(7/32) = .4375
expected(black) = -1(23/32) = -0.71875
add them up to get -0.03125
A "losing" game
expected(silver) = $2(7/32) = .4375
expected(black) = -1(23/32) = -0.71875
add them up to get -0.03125
A "losing" game
Answered by
tatiana
Thanks
Answered by
Daniel Gonzalez
Very close. You just need to subtract the 1$ entrance fee from every prize pool.
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