Asked by shanquessa
Hi, I am taking Algebra 2 and I need help with some Substitution method problems:
x+12y=68
x=8y-12
x+3y=7
2x-4y=24
3a+b=3
2a-5b=-15
-6=3x-6y
4x=4+5y
x+12y=68
x=8y-12
x+3y=7
2x-4y=24
3a+b=3
2a-5b=-15
-6=3x-6y
4x=4+5y
Answers
Answered by
drwls
I'll do one for you. They all work the same way. You need the practice doing them yourself.
Substitute 8y - 12 for x in the first equation.
8y - 12 + 12y = 68
20 y = 80
y = 4
x = 8y - 12 = 32 - 12 = 20
Substitute 8y - 12 for x in the first equation.
8y - 12 + 12y = 68
20 y = 80
y = 4
x = 8y - 12 = 32 - 12 = 20
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.