Asked by angy
Consider a stationary skater of mass 60 kg. Another skater of mass 40kg rushes and holds the first at a speed of 12km/hr. Both skaters hold together and move as one system (S) with a speed V.
a) Determine V.
b) Determine the kinetic energy of (S) before and after collision.
a) Determine V.
b) Determine the kinetic energy of (S) before and after collision.
Answers
Answered by
bobpursley
conservation of momentum:
60(0)+40(12)=(60+40)V
solve for b.
Ke before= 1/2 40*12^2
KE after= 1/2 (100)V^2
60(0)+40(12)=(60+40)V
solve for b.
Ke before= 1/2 40*12^2
KE after= 1/2 (100)V^2
Answered by
Hoda
Hoda
There are no AI answers yet. The ability to request AI answers is coming soon!