Asked by Tim
I have a summation formula for Fibonacci numbers.
n
(SUM)F(2i)=F(2n+1)-1
i=0
When the i value is changed from zero, and is then subbed into F(2i)the equation will not work. (RHS wont = LHS)
eg: i=2 n=3
3
(SUM)F(4)=F(7)-1
i=2
I understand the summation bit, (it =3)
But what does it then do to the F(4) part? ie: it becomes: 3F(4).
3*F(4)=9
F(7)-1=12.
What am i supposed to be doing?
n
(SUM)F(2i)=F(2n+1)-1
i=0
When the i value is changed from zero, and is then subbed into F(2i)the equation will not work. (RHS wont = LHS)
eg: i=2 n=3
3
(SUM)F(4)=F(7)-1
i=2
I understand the summation bit, (it =3)
But what does it then do to the F(4) part? ie: it becomes: 3F(4).
3*F(4)=9
F(7)-1=12.
What am i supposed to be doing?
Answers
Answered by
Reiny
Check your typing.
The first few Fibonacci numbers are
1 1 2 3 5 8 13 21 34 55 ...
In the generally accepted notation, these would be F(1)=1, F(2)=1, F(3)=2 etc.
F(0) has no meaning in this general notation.
So let's try your formula for n=3
The i would then go 0,1,2,3
and the Left Side would be
F(0) + F(2) + F(4) + F(6)
which would be ? + 1 + 3 + 8
Right Side = F(7) - 1 = 12
Your formula makes no sense
From where are you getting calculations such as 3F(4) above?
The first few Fibonacci numbers are
1 1 2 3 5 8 13 21 34 55 ...
In the generally accepted notation, these would be F(1)=1, F(2)=1, F(3)=2 etc.
F(0) has no meaning in this general notation.
So let's try your formula for n=3
The i would then go 0,1,2,3
and the Left Side would be
F(0) + F(2) + F(4) + F(6)
which would be ? + 1 + 3 + 8
Right Side = F(7) - 1 = 12
Your formula makes no sense
From where are you getting calculations such as 3F(4) above?
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