Identify the oxidation-reduction reactions among the following:

1. Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)

2. 2Na(s) + Cl2(aq) → 2NaCl(s)

3. 2Mg(s) + O2(g) → 2MgO

1 and 2 only
2 and 3 only
1 and 3 only
All of 1, 2, and 3
None of 1, 2, and 3

2 answers

Oxidation is the loss of electrons. Reduction is the gain of e.electrons.
For 1.
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)

Zn on left has oxidation state (OS) of 0. Zn on right has(OS) of +2. So that's a loss of 2e which makes Zn to Zn^2+ oxidation.
Cu^2+ on the left has OS of 2+. On the right it is zero. That's a gain of 2e which makes Cu^2+ reduced.
So check out 2 and 3 and you can answer the question.
Good Morning DrBob222, My answer is all of 1,2,and 3. Please let me know if I am on the right track.

2) 2na=2na+2e (oxidation)
Cl2+2e-=2Cl- (reduction)

3) 2Mg=Mg2+ +4e (oxidation)
O2+4e-=2O2 (oxidation)
Similar Questions
  1. What makes this an oxidation-reaction? 3Ag2S+2Al(s) -> Al2S3+6 Ag(s)?Write the half-reactions showing the oxidation and
    1. answers icon 2 answers
  2. Which of the following is true about oxidation reactions?A. Oxidation reactions are the principal source of energy on Earth. B.
    1. answers icon 2 answers
  3. Identify the oxidation-reduction reactions among the following:1. Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s) 2. 2Na(s) + Cl2(aq) →
    1. answers icon 1 answer
  4. 2 Al + 3 Cu(NO3)2 --> 2 Al(NO3)3 + 3 Cu1. Write balanced equations for the oxidation and reduction half-reactions. Identify each
    1. answers icon 0 answers
more similar questions