Asked by Anonymous
A high-speed drill rotating ccw at 2300 rpm comes to a halt in 2.9 s .
Answers
Answered by
Damon
you do not say what the question is
average rpm during stop = 1150
turns to stop = 1150 *2.9/60
original radians/s
= 2300 revs/min*2 pi rad/rev *1min/60 s
= 241 radians/s
angular acceleration = -241/2.9
whatever
average rpm during stop = 1150
turns to stop = 1150 *2.9/60
original radians/s
= 2300 revs/min*2 pi rad/rev *1min/60 s
= 241 radians/s
angular acceleration = -241/2.9
whatever
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