Asked by molly
Hi, sorry to bother you. but can you please help me with this problem
z=log(e^(5y))
Thanks!
z=log(e^(5y))
Thanks!
Answers
Answered by
Steve
That is not a problem. It is an equation. The problem is to find what you want to do with it.
I'll assume you want to solve for y.
I'll also assume that by log you mean natural log. If so, then
z=log(e^(5y)) = 5y
y = z/5
If by chance you meant log base 10, then
10^z = e^(5y)
ln(10^z) = 5y
5y = z ln10
y = (z ln10)/5
or, y = z/(5 log(e))
I'll assume you want to solve for y.
I'll also assume that by log you mean natural log. If so, then
z=log(e^(5y)) = 5y
y = z/5
If by chance you meant log base 10, then
10^z = e^(5y)
ln(10^z) = 5y
5y = z ln10
y = (z ln10)/5
or, y = z/(5 log(e))
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.