Question
Hi, sorry to bother you. but can you please help me with this problem
z=log(e^(5y))
Thanks!
z=log(e^(5y))
Thanks!
Answers
Steve
That is not a problem. It is an equation. The problem is to find what you want to do with it.
I'll assume you want to solve for y.
I'll also assume that by log you mean natural log. If so, then
z=log(e^(5y)) = 5y
y = z/5
If by chance you meant log base 10, then
10^z = e^(5y)
ln(10^z) = 5y
5y = z ln10
y = (z ln10)/5
or, y = z/(5 log(e))
I'll assume you want to solve for y.
I'll also assume that by log you mean natural log. If so, then
z=log(e^(5y)) = 5y
y = z/5
If by chance you meant log base 10, then
10^z = e^(5y)
ln(10^z) = 5y
5y = z ln10
y = (z ln10)/5
or, y = z/(5 log(e))