Question
A 51kg person on a merry-go-round is traveling in a circle with a radius of 2 m at a speed of 6 m/s
A) What acceleration does the person experience?
B) What is the net horizontal force?
C) How does it compare with the person's weight?
A) What acceleration does the person experience?
B) What is the net horizontal force?
C) How does it compare with the person's weight?
Answers
Damon
Ac = v^2/r = 36/2 = 18 m/s^2
m
F = M Ac = 51 *18 Newtons
weight = 51 * 9.81 Newtons
almost 2 g
m
F = M Ac = 51 *18 Newtons
weight = 51 * 9.81 Newtons
almost 2 g
bobpursley
acceleration= v^2/r
force=mass*acceleration
weight=51*9.8 N
force=mass*acceleration
weight=51*9.8 N