Asked by value

a bullet of mass 0.03kg enters a block of wood with a velocity 600m/s & penatrate to a depth of 0.2m .Calculate the average force of the wood to the penetration of the bullet
Answered by value
60000
Answered by 0.2, 0.03, 600
27000
Answered by Damon
change of momentum = .03*600 = 18

average speed = 300
time = .2/300

Force = change of momentum/change of time
= 18 *300/.2 Newtons
= 90*300
=27,000 agree
Answered by SANJAY
Thanks sir
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