Asked by Kabw
I was given a solution of HCOOH with hand approximate concentration of 0.20 moles and I need to titrate this with a 0.110 V mol of NaOH. If I add 20 milliliters of hcooh to the beaker before I titrate approximately what volume of NaOH will be required to reach the endpoint?
Answers
Answered by
bobpursley
Molarity acid*volumeacid=Molaritybase*volumebase
VolumeBAse=.2*20ml/.110=36.4ml appx
VolumeBAse=.2*20ml/.110=36.4ml appx
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