Asked by Larry
Independent Events
Two dice are rolled. What is te probability of each event?
1. The numbers total 9.
2. The numbers total 2.
3. Both dice display the same number.
4. The sum of the numbers is not 8.
Please help, I don't get this.
Two dice are rolled. What is te probability of each event?
1. The numbers total 9.
2. The numbers total 2.
3. Both dice display the same number.
4. The sum of the numbers is not 8.
Please help, I don't get this.
Answers
Answered by
economyst
With two (fair) dice, there are 6*6=36 possible rolls. (1-1, 1-2, 1-3, ... 6-6) (hint: you could easily write all possible outcomes on a piece of paper)
So, to get 9, one could have a 6-3, 3-6, 4-5, or 5-4. So, the probability is 4/36 = .11111.
Take it from here
So, to get 9, one could have a 6-3, 3-6, 4-5, or 5-4. So, the probability is 4/36 = .11111.
Take it from here
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