Asked by joe
Tony invests $3900 in two different accounts. The first account paid 6 %, the second account paid 8 % in interest. At the end of the first year he had earned $280 in interest. How much was in each account?
Answers
Answered by
Reiny
amount invested at 6% ---- x
amount invested at 8% ---- 3900-x
.06x + .08(3900-x) = 280
times 100
6x + 8(3900-x) = 28000
continue
amount invested at 8% ---- 3900-x
.06x + .08(3900-x) = 280
times 100
6x + 8(3900-x) = 28000
continue
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