Question
During an auto race, a car with a speed of 85m/s acceleration passed another car rate of 4.0m/s^2 for 3.5s. How far does the car travel during this time?
Okay so I used D= Vi-t+(1/2)t^2
D= 85m-4.0m/s^2+(1/2)3.5^2
D= 87.125 ?
Okay so I used D= Vi-t+(1/2)t^2
D= 85m-4.0m/s^2+(1/2)3.5^2
D= 87.125 ?
Answers
Henry
d = Vo*t + 0.5a*t^2.
d = 85*3.5 + 0.5*4*3.5^2 = 322 m.
d = 85*3.5 + 0.5*4*3.5^2 = 322 m.