Asked by Joesph
How high can a person (assume a weight of 70 kg) climb on one ounce of chocolate if the heat of combustion (628 kJ) can be converted completely into work associated with vertical displacement?
Answers
Answered by
Scott
E = m g h ... h = E / (m g)
h = 628 kJ / (70 kg * 9.81 m/s^2)
1 Joule = 1 kg m/s^2
h = 628 kJ / (70 kg * 9.81 m/s^2)
1 Joule = 1 kg m/s^2
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