Asked by Anonymous
A Zip-liner is gliding along a horizontal wire over a lake. They must release themselves from the wire and drop down to the water to get off the zip-line. They are 6.50 m above the water and release themselves when they are travelling at 2.20 m/s. How fast are they travelling when they hit the water?
Answers
Answered by
Henry
Y^2 = Yo^2 + 2g*h = 0 + 19.6*6.5 = 127.4, Y = 11.29 m/s.
V = sqrt(Xo^2+Y^2) = sqrt(2.2^2 + 11.29^2) = 11.50 m/s
V = sqrt(Xo^2+Y^2) = sqrt(2.2^2 + 11.29^2) = 11.50 m/s
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