Asked by Andy
                Dick is younger than Tom, but older than Harry. Their ages in years are consecutive odd integers. Dick's mother is three times as old as Dick, and she is also 13 years older than twice as old as Tom. How old are Harry, Dick, and Tom
            
            
        Answers
                    Answered by
            Scott
            
    H < D < T
H + 2 = D ... D + 2 = T
3 D = 2 T + 13
3 D = 2 (D + 2) + 13 = 2 D + 17
    
H + 2 = D ... D + 2 = T
3 D = 2 T + 13
3 D = 2 (D + 2) + 13 = 2 D + 17
                    Answered by
            Bosnian
            
    D = Dick's age
T = Tom's age
H = Harry's age
M = Mother's age
D < T
D > H
D = T - 2 Add 2 to both sides
D + 2 = T - 2 + 2
D + 2 = T
T = D + 2
M = 3 D
also:
M = 2 T + 13 = 2 ( D + 2 ) + 13 = 2 * D + 2 * 2 + 13 = 2 D + 4 + 13 = 2 D + 17
M = M
3 D = 2 D + 17 Subtract 2 D to both sides
 
3 D - 2 D = 2 D + 17 - 2 D
D = 17 yrs
T = D + 2 = 17 + 2 = 19 yrs
D = H + 2 Subtract 2 to both sides
D - 2 = H + 2 - 2
D - 2 = H
H = D - 2
H = 17 - 2 = 15 yrs
Proof:
Dick's mother is three times as old as Dick:
M = 3 D = 3 * 17 = 51 yrs
Dick's mother is 13 years older than twice as old as Tom:
M = 2 T + 13 = 2 * 19 + 13 = 38 + 13 = 51 yrs
    
T = Tom's age
H = Harry's age
M = Mother's age
D < T
D > H
D = T - 2 Add 2 to both sides
D + 2 = T - 2 + 2
D + 2 = T
T = D + 2
M = 3 D
also:
M = 2 T + 13 = 2 ( D + 2 ) + 13 = 2 * D + 2 * 2 + 13 = 2 D + 4 + 13 = 2 D + 17
M = M
3 D = 2 D + 17 Subtract 2 D to both sides
3 D - 2 D = 2 D + 17 - 2 D
D = 17 yrs
T = D + 2 = 17 + 2 = 19 yrs
D = H + 2 Subtract 2 to both sides
D - 2 = H + 2 - 2
D - 2 = H
H = D - 2
H = 17 - 2 = 15 yrs
Proof:
Dick's mother is three times as old as Dick:
M = 3 D = 3 * 17 = 51 yrs
Dick's mother is 13 years older than twice as old as Tom:
M = 2 T + 13 = 2 * 19 + 13 = 38 + 13 = 51 yrs
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