a child and a bicycle have a mass of 45kg together. The child rides the bicycle 1800m in 10 min at a constant speed. what is the kinetic energy of the system?

User Icon for bobpursley bobpursley answered
8 years ago

KE=1/2 m v^2=1/2 *45*(1800/600)^2 in Joules

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To calculate the kinetic energy of the system, we need to calculate the total mass and the velocity of the system.

Given:
Mass of the child and bicycle together, m = 45 kg
Distance covered, d = 1800 m
Time taken, t = 10 min

First, let's convert the time from minutes to seconds:
10 min * 60 sec/min = 600 sec

Next, we can calculate the velocity of the system using the formula: Velocity (v) = Distance (d) / Time (t)
v = 1800 m / 600 sec = 3 m/s

Now, we can calculate the kinetic energy (KE) of the system using the formula: KE = 1/2 * mass * velocity^2
KE = 1/2 * 45 kg * (3 m/s)^2
KE = 1/2 * 45 kg * 9 m^2/s^2

Finally, we can calculate the kinetic energy of the system:
KE = 202.5 joules

Therefore, the kinetic energy of the system is 202.5 joules.

User Icon for Explain Bot Explain Bot answered
1 year ago

To find the kinetic energy of the system, we need to calculate the total mass and the velocity of the system.

Step 1: Find the mass of the system
Given that the child and the bicycle have a combined mass of 45 kg, we can assign this value to the mass of the system.

System Mass = 45 kg

Step 2: Find the velocity of the system
To determine the velocity of the system, we need to convert the distance traveled and the time taken into meters per second (m/s).

Distance Traveled = 1800 m
Time Taken = 10 min = 600 s

Velocity = Distance / Time = 1800 m / 600 s = 3 m/s

Step 3: Calculate the kinetic energy of the system
The formula for kinetic energy is given by:

Kinetic Energy = (1/2) * Mass * Velocity^2

Substitute the values we found into the formula:

Kinetic Energy = (1/2) * 45 kg * (3 m/s)^2
= (1/2) * 45 kg * 9 m^2/s^2
= 202.5 Joules

Therefore, the kinetic energy of the system is 202.5 Joules.