Asked by kled
a man pushes a lawnmower 50ft in 5s by exerting a force of 30lb at an angle of 53degrees with the horizon. find the work done and the average power expended in horsepower.
Answers
Answered by
bobpursley
work done+horizontalforce*distance
= 30cos53*50 ft lbs
power? divide it by 5 seconds.
then convert ftlbs/sec to hp
= 30cos53*50 ft lbs
power? divide it by 5 seconds.
then convert ftlbs/sec to hp
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