Asked by Wawen
Integrate it in step by step applying integration by partial fraction.
∫(x^2)/(x^2+1)dx
∫(x^2)/(x^2+1)dx
Answers
Answered by
Reiny
do one step of a long division to get
(x^2)/(x^2+1)
= 1 - 1/(x^2+1)
∫(x^2)/(x^2+1)dx
= ∫( 1 - 1/(x^2+1))dx
= x - tan^-1 (x) + c ,
the last part should be part of your repertoire of integrals
(x^2)/(x^2+1)
= 1 - 1/(x^2+1)
∫(x^2)/(x^2+1)dx
= ∫( 1 - 1/(x^2+1))dx
= x - tan^-1 (x) + c ,
the last part should be part of your repertoire of integrals
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