Asked by Fred
You are on a new planet and want to know the acceleration due to gravity. You take a ball and kick it at an angle of 26.0° at a speed of 21.0 m/s. If the ball is in the air for 7.30 s, what is the magnitude of the acceleration due to gravity?
Answers
Answered by
Steve
You know that the height h is
h = v*sinθ t - g/2 t^2
So, solve for g in
21.0 sin26.0° * 7.3 - g/2 * 7.3^2 = 0
g = 2.52 m/s^2
h = v*sinθ t - g/2 t^2
So, solve for g in
21.0 sin26.0° * 7.3 - g/2 * 7.3^2 = 0
g = 2.52 m/s^2
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