two sides of a triangle are 15cm and 18 cm in length. the altitude tossed is 10cm what is the length of the altitude to the 15 cm side?
2 answers
is 15 the correct answer
What is a tossed altitude ?
I will assume the question is as follows:
Triangle ABC, AB = 15 , AC = 18
AD is an altitude where D is on BC and BD = 10
BD^2 + 10^2 = 15^2
BD = √125 = 5√5
similarly, CD = √224 = 4√14
BC = appr 26.147 cm
Let the altitude from C to BA extended be CE, where E is on BA extended.
I will let you do some work ....
you can find angle BAC using the cosine law, it will be obtuse.
Then in the right-angled triangle EAC you can find angle EAC and you know the hypotenuse AC = 18, so you can find the altitude CE
angle EAC
I will assume the question is as follows:
Triangle ABC, AB = 15 , AC = 18
AD is an altitude where D is on BC and BD = 10
BD^2 + 10^2 = 15^2
BD = √125 = 5√5
similarly, CD = √224 = 4√14
BC = appr 26.147 cm
Let the altitude from C to BA extended be CE, where E is on BA extended.
I will let you do some work ....
you can find angle BAC using the cosine law, it will be obtuse.
Then in the right-angled triangle EAC you can find angle EAC and you know the hypotenuse AC = 18, so you can find the altitude CE
angle EAC
2 answers