Question
A 150L water heater is set to a cutoff temperature of 49 degrees C and that the incoming water is at 298K, calculate the energy in kJ needed to get this 150L water to it's maximum temperature. Please help!
Answers
bobpursley
heat energy=mc deltaTemp
= 150kg*specificheatwater*(49+273-298)
look up specific heat of water, and you have it.
= 150kg*specificheatwater*(49+273-298)
look up specific heat of water, and you have it.
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