Asked by Hannah

A 150L water heater is set to a cutoff temperature of 49 degrees C and that the incoming water is at 298K, calculate the energy in kJ needed to get this 150L water to it's maximum temperature. Please help!

Answers

Answered by bobpursley
heat energy=mc deltaTemp
= 150kg*specificheatwater*(49+273-298)
look up specific heat of water, and you have it.
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