Asked by Pooka
Six years hence a man 's age will be three times his son 's age and three years ago,he was nine times as old as his son .find their present ages
Answers
Answered by
Reiny
6 years from now:
son's age ---- x
man's age --- 3x
present time: (subtract 6)
son's age --- x-6
man's age -- 3x-6
three years from now: (subtract 3)
son's age = x-9
man's age = 3x - 9
3x-9 = 9(x-9)
3x - 9 = 9x - 81
72 = 6x
x = 12
son's present age = 12-6 = 6 years
father's age = 36-6 = 30 years
son's age ---- x
man's age --- 3x
present time: (subtract 6)
son's age --- x-6
man's age -- 3x-6
three years from now: (subtract 3)
son's age = x-9
man's age = 3x - 9
3x-9 = 9(x-9)
3x - 9 = 9x - 81
72 = 6x
x = 12
son's present age = 12-6 = 6 years
father's age = 36-6 = 30 years
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