Asked by WON
1. Determine the resultant of each vector sum
a) 45 km/h vertically and then 75 km/h horizontally.
b) 300 m east and then 400 m N45¡ÆE
a) 45 km/h vertically and then 75 km/h horizontally.
b) 300 m east and then 400 m N45¡ÆE
Answers
Answered by
Reiny
45 km/h vertically and then 75 km/h horizontally
--->45(cos90°, sin90°) + 75(cos0, sin0)
= (45(0,1) + 75(1,0)
= (0,45) + (75,0)
= (75,45)
magnitude = √(75^+45^2) = √7650
= 15√34
direction vector: tanØ = 45/75
Ø = appr 30.96°
or
you have a right-angled triangle, and the hypotenuse is √(75^2+45^2)
b) resultant = 300(-1,0) + 400(cos45,sin45)
= (300, 0) + (200√2 , 200√2)
= ( 200√2 + 300, 200√2)
follow the same steps I used for the first part
--->45(cos90°, sin90°) + 75(cos0, sin0)
= (45(0,1) + 75(1,0)
= (0,45) + (75,0)
= (75,45)
magnitude = √(75^+45^2) = √7650
= 15√34
direction vector: tanØ = 45/75
Ø = appr 30.96°
or
you have a right-angled triangle, and the hypotenuse is √(75^2+45^2)
b) resultant = 300(-1,0) + 400(cos45,sin45)
= (300, 0) + (200√2 , 200√2)
= ( 200√2 + 300, 200√2)
follow the same steps I used for the first part
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