Asked by Tom
A box of mass m slides down an inclined plane that makes an angle of φ with the horizontal. If the coefficient of kinetic friction is μk, find an expression for the acceleration of the box down the slope.
The acceleration due to gravity is g.
a. g ( cosφ + μksinφ)
b. g ( cosφ - μksinφ)
c. g ( sinφ - μkcosφ )
d. g ( sinφ + μkcosφ )
The acceleration due to gravity is g.
a. g ( cosφ + μksinφ)
b. g ( cosφ - μksinφ)
c. g ( sinφ - μkcosφ )
d. g ( sinφ + μkcosφ )
Answers
Answered by
Damon
g force down slope = mg sin phi
friction force up slope = mu mg cos phi
a = F/m = g sin phi - mu g cos phi
= g (sin phi - mu cos phi)
friction force up slope = mu mg cos phi
a = F/m = g sin phi - mu g cos phi
= g (sin phi - mu cos phi)
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