p=1/r * s + d ; solve for s
A. s = r/p - d
B. s = p + d/r
C. s = r(p - d)
D. s = r(p + d)
I'm not sure on this one, but I'd go with B. Please help? Thanks
5 answers
nope, if you subtract d from both sides, you know you will have a term p-d in it.
Okay, is it A then?
stop guessing and start working
1/r * s = s/r, so
p=s/r + d
p-d = s/r
Now what do you think?
1/r * s = s/r, so
p=s/r + d
p-d = s/r
Now what do you think?
Anyway, this is how you solve:
p=1/r*s+d
p-d=1/r*s+d-d
r(p-d)=r(1/r)+s
r(p-d)=s
^ so i just subtracted d from both sides of the equation, so I could get rid of the d and isolate s. Then I multiplied by r on both sides of the equation to get rid of the r and isolate s.
p=1/r*s+d
p-d=1/r*s+d-d
r(p-d)=r(1/r)+s
r(p-d)=s
^ so i just subtracted d from both sides of the equation, so I could get rid of the d and isolate s. Then I multiplied by r on both sides of the equation to get rid of the r and isolate s.
1. [d.] 37
2. [d.] 512
3. [a.] rational
4. [a.] (dot between 1 & 2)
5. [b.] (greater than sign)
6. [a.] associative property of addition
7. [c.] distributive property
8. [a.] 5y - 4
9. [a.] 12 + 3x
10. [b.] 10d + 6b + s; $86.00
11. [c.] s = r(p - d)
12. [a.] 12 > 6 + n
13. [a.] (full dot on 4; line going back)
14. [a.] (half dot on -2, full on 0; line between)
15. [c.] x = 1 and x = -4
16. [a.] -2 ≤ x ≤ 3
17. [c.] x < -20 or x > 20
2. [d.] 512
3. [a.] rational
4. [a.] (dot between 1 & 2)
5. [b.] (greater than sign)
6. [a.] associative property of addition
7. [c.] distributive property
8. [a.] 5y - 4
9. [a.] 12 + 3x
10. [b.] 10d + 6b + s; $86.00
11. [c.] s = r(p - d)
12. [a.] 12 > 6 + n
13. [a.] (full dot on 4; line going back)
14. [a.] (half dot on -2, full on 0; line between)
15. [c.] x = 1 and x = -4
16. [a.] -2 ≤ x ≤ 3
17. [c.] x < -20 or x > 20
1 answer