Asked by Kathleen

For this section, use the following distributions: 1) A direwolf has a 70% probability of killing a stag upon encounter; 2) a dire wolf awakens the village on average 1.2 times per six weeks; 3) a dire wolf will eat an amount that is uniformly distributed between 10-24 pounds per week; 4) the weight of an average dire wolf is normally distributed with an average of 150 lbs and a standard deviation of 21.43 pounds.

Show which is more likely:
A dire wolf eating exactly 15lbs of food next week or a direwolf weighing exactly 170 lbs.

I know the answer is that both are 0, but I'm not sure how to get there.
Thanks!!
Answered by PsyDAG
Neither probability = 0.

Weight

Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

Food

24 - 10 = 14

(15-10)/14 = ?
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