Asked by Logan
Let me try writing it again...
(X/2)^3*(X/2)^4
---------------------
(X/2^3)^2
I keep getting X/2^6, but the book says X/2^5. How do you get X/2^5????
(X/2)^3*(X/2)^4
---------------------
(X/2^3)^2
I keep getting X/2^6, but the book says X/2^5. How do you get X/2^5????
Answers
Answered by
John1
You keep the base and add the exponents
in the numerator
(x/2)^7
in the denominator it looks like you are raising a power to a power..
so you keep the base and multiply the two powers
denominator should be (x/2)^6
I don't know where the 5 is coming from in your answer... unless I am not understanding what the problem actually said or maybe you have a typo.
My answer would be x/2 because 7 -6 = power of 1.
in the numerator
(x/2)^7
in the denominator it looks like you are raising a power to a power..
so you keep the base and multiply the two powers
denominator should be (x/2)^6
I don't know where the 5 is coming from in your answer... unless I am not understanding what the problem actually said or maybe you have a typo.
My answer would be x/2 because 7 -6 = power of 1.
Answered by
Logan
Thank you!! It must be a typo in the book. Singapore Math. I appreciate all of your help!!
Answered by
Reiny
books have been know to be wrong, as do most teachers and students.
from the way you typed it, the simplified answer is
(x/2)^7 / (x/2)^6
= x/2
John1's explanation is correct
from the way you typed it, the simplified answer is
(x/2)^7 / (x/2)^6
= x/2
John1's explanation is correct
Answered by
Logan
Thank you!! It must be a typo in the book. Singapore Math. I appreciate all of your help!!
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