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I can't quite write the problem, so I'll try to explain it as best I can. In exponents and in fractions... (X/2) to the 3rd pow...Asked by Logan
I can't quite write the problem, so I'll try to explain it as best I can. In exponents and in fractions...
(X/2) to the 3rd power times (X/2) to the 4th power...all over,or divided by, (X/2 to the 3rd power) to the 2nd power.
The book says the answer is X/2 to the 5th power. How is this answer found???? I keep getting X/2 to the 6th power ☹️
(X/2) to the 3rd power times (X/2) to the 4th power...all over,or divided by, (X/2 to the 3rd power) to the 2nd power.
The book says the answer is X/2 to the 5th power. How is this answer found???? I keep getting X/2 to the 6th power ☹️
Answers
Answered by
John1
I answered above.. but this is clearer...
keep the base and add the powers when multiplying (x/2)^7
When raising a power to a power keep the base and multiply the 2 powers.
(x/2)^6
Again when dividing, keep the base and subtract the exponents. I still get (x/2)^1 or (x/2)
Sometimes books do have the wrong answer. I used to work for book companies and my job was to find the wrong answers so they could be fixed.
keep the base and add the powers when multiplying (x/2)^7
When raising a power to a power keep the base and multiply the 2 powers.
(x/2)^6
Again when dividing, keep the base and subtract the exponents. I still get (x/2)^1 or (x/2)
Sometimes books do have the wrong answer. I used to work for book companies and my job was to find the wrong answers so they could be fixed.
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