Asked by John walk
a car starting from rest accelerates uniformly at 5.4m/s^2. how much time does it take for the car to go 145m
Answers
Answered by
Reiny
a = 5.4
v = 5.4t + c
but v = 0 when t = 0 , so c = 0
v = 5.4t
s = 2.7t^2 + k
but s = 0, when t = 0 , so k=0
2.7t^2 = 145
t^2 = 145/2.7
t = ....
v = 5.4t + c
but v = 0 when t = 0 , so c = 0
v = 5.4t
s = 2.7t^2 + k
but s = 0, when t = 0 , so k=0
2.7t^2 = 145
t^2 = 145/2.7
t = ....
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